When first the 70 stems was unravelled succesfully, the great expectation was to find a relation between these 70 stems of two signs, and the 75 isolated stem elements
missing one unit. Here arranged in my first and still highest priority illustration.
The second advancement was the gnomonical arrangement of the above relations, which possess the quality, that it utilize a master-proposal
for the quantitativ identity of the absent units, in that the two halfs will be equal. Note the fingerpost 'multipla eleven'.
Then I did allow myself to turn this magic kaleidoscope an inch further, to study its next
reflexions in the hope thereby to unriddle exatly what absent units belong in which signgroups. Those experiments involved square numbers of a step pyramid: 144 +100 +(64 +36 +16 + 4 + 1) =365. The signs in hierarchical order. -All signgroups on
Through a wealth of similar small observations, which with sovereignity undermine any earlier notions of the signgroups as written words, I gained an intimate knowledge for the calendrical structure of
the inscription, so I could say, as the first, that I had retrieved this secret from our Cretan ancestors: The Minoan calendar.
THE DISTRIBUTION OF ALL UNITS INTO VARIOUS GROUPS
the 50 stem-signgroups consist of 290 units in total (thorns incl.), which go 29 x10, - and the 11 reduced signgroups hold 75 units, or 29 x2, +17.